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Where can I download the latest Oracle dumps for free Oracle 1Z0-808 dumps? “Java SE 8 Programmer I” is the name of Oracle 1Z0-808 exam dumps which covers all the knowledge points of the real Oracle exam. Real Oracle 1Z0-808 dumps pdf exam are the best materials. Pass4itsure Oracle 1Z0-808 dumps exam questions answers are updated (236 Q&As) are verified by experts.

The associated certifications of 1Z0-808 dumps is Oracle Certified Associate, Java SE 8 Programmer.There are total 72 Questions in the exam which include multiple choice questions with a single response option, multiple response and matching items. The allocated time to solve the https://www.pass4itsure.com/1z0-808.html dumps exam is 150 minutes.

Exam Code: 1Z0-808
Exam Name: Java SE 8 Programmer I
Q&As: 236

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QUESTION 11
Given the code fragment:
1Z0-808 dumps

What is the result?
A. 10 8 6 4 2 0
B. 10 8 6 4 2
C. AnArithmeticException is thrown at runtime
D. The program goes into an infinite loop outputting: 10 8 6 4 2 0. . .
E. Compilation fails
1Z0-808 exam Correct Answer: B
Explanation
QUESTION 12
Given:

1Z0-808 dumps

Which code fragment, when inserted at line 14, enables the code to print Mike Found?
A. int f = ps.indexOf {new patient (“Mike”)};
B. int f = ps.indexOf (patient(“Mike”));
C. patient p = new Patient (“Mike”);
int f = pas.indexOf(P)
D. int f = ps.indexOf(p2);
1Z0-808 dumps Correct Answer: C
Explanation
QUESTION 13
Given:
1Z0-808 dumps

Which code fragment should you use at line n1 to instantiate the dvd object successfully?
1Z0-808 dumps

A. Option A
B. Option B
C. Option C
D. Option D
1Z0-808 pdf Correct Answer: C
Explanation
QUESTION 14
Given the for loop construct:
for ( expr1 ; expr2 ; expr3 ) {
statement;
}
Which two statements are true?
A. This is not the only valid for loop construct; there exits another form of for loop constructor.
B. The expression expr1 is optional. it initializes the loop and is evaluated once, as the loop begin.
C. When expr2 evaluates to false, the loop terminates. It is evaluated only after each iteration through the loop.
D. The expression expr3 must be present. It is evaluated after each iteration through the loop.
1Z0-808 vce Correct Answer: BC
Explanation
Explanation/Reference:
The for statement have this forms:
for (init-stmt; condition; next-stmt) {
body
}
There are three clauses in the for statement.
The init-stmt statement is done before the loop is started, usually to initialize an iteration variable.
The condition expression is tested before each time the loop is done. The loop isn’t executed if the boolean expression is false (the same as the while loop). The
next-stmt statement is done after the body is executed. It typically increments an iteration variable.
QUESTION 15
Which three statements are true about the structure of a Java class?
A. A class can have only one private constructor.
B. A method can have the same name as a field.
C. A class can have overloaded static methods.
D. A public class must have a main method.
E. The methods are mandatory components of a class.
F. The fields need not be initialized before use.
1Z0-808 exam Correct Answer: ABC
Explanation
Explanation/Reference:
Explanation: A: Private constructors prevent a class from being explicitly instantiated by its callers.
If the programmer does not provide a constructor for a class, then the system will always provide a default, public no-argument constructor. To disable this default
constructor, simply add a private no-argument constructor to the class. This private constructor may be empty.
B: The following works fine:
int cake() {
int cake=0;
return (1);
}
C: We can overload static method in Java. In terms of method overloading static method are just like normal methods and in order to overload static method you
need to provide another static method with same name but different method signature.
Incorrect:
Not D: Only a public class in an application need to have a main method.
Not E:
Example:
class A
{
public string something;
public int a;

}
Q: What do you call classes without methods?
Most of the time: An anti pattern.
Why? Because it faciliates procedural programming with “Operator” classes and data structures. You separate data and behaviour which isn’t exactly good OOP.
Often times: A DTO (Data Transfer Object)
Read only datastructures meant to exchange data, derived from a business/domain object.
Sometimes: Just data structure.
Well sometimes, you just gotta have those structures to hold data that is just plain and simple and has no operations on it.
Not F: Fields need to be initialtized. If not the code will not compile.
Example:
Uncompilable source code – variable x might not have been initialized
QUESTION 16
View the exhibit.
1Z0-808 dumps

Given the code fragment:
1Z0-808 dumps

Which change enables the code to print the following?
James age: 20
Williams age: 32
A. Replacing line 5 with public static void main (String [] args) throws MissingInfoException, AgeOutofRangeException {
B. Replacing line 5 with public static void main (String [] args) throws.Exception {
C. Enclosing line 6 and line 7 within a try block and adding:
catch(Exception e1) { //code goes here}
catch (missingInfoException e2) { //code goes here} catch (AgeOutofRangeException e3) {//code goes here}
D. Enclosing line 6 and line 7 within a try block and adding:
catch (missingInfoException e2) { //code goes here} catch (AgeOutofRangeException e3) {//code goes here}
1Z0-808 dumps Correct Answer: C
Explanation
QUESTION 17
Given the code fragment:
public static void main(String[] args) {
int iArray[] = {65, 68, 69};

iArray[2] = iArray[0];
iArray[0] = iArray[1];
iArray[1] = iArray[2];
for (int element : iArray) {
System.out.print(element + ” “);
}
A. 68, 65, 69
B. 68, 65, 65
C. 65, 68, 65
D. 65, 68, 69
E. Compilation fails
1Z0-808 pdf Correct Answer: B
Explanation
QUESTION 18
Given:
public class Test {
public static void main(String[] args) {
int day = 1;
switch (day) {
case “7”: System.out.print(“Uranus”);
case “6”: System.out.print(“Saturn”);
case “1”: System.out.print(“Mercury”);
case “2”: System.out.print(“Venus”);
case “3”: System.out.print(“Earth”);
case “4”: System.out.print(“Mars”);
case “5”: System.out.print(“Jupiter”);
} } }
Which two modifications, made independently, enable the code to compile and run?
A. Adding a break statement after each print statement
B. Adding a default section within the switch code-block
C. Changing the string literals in each case label to integer
D. Changing the type of the variable day to String
E. Arranging the case labels in ascending order
1Z0-808 vce Correct Answer: AC
Explanation
Explanation/Reference:
Explanation: The following will work fine:
public class Test {
public static void main(String[] args) {
int day = 1;
switch (day) {
case 7: System.out.print(“Uranus”); break;
case 6: System.out.print(“Saturn”); break;
case 1: System.out.print(“Mercury”); break;
case 2: System.out.print(“Venus”); break;
case 3: System.out.print(“Earth”); break;
case 4: System.out.print(“Mars”); break;
case 5: System.out.print(“Jupiter”); break;
}}}

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